Optimal. Leaf size=245 \[ \frac{\sqrt{a+b x+c x^2} \left (2 c e x \left (-4 c e (3 a e+2 b d)+5 b^2 e^2+8 c^2 d^2\right )-8 c^2 d e (16 a e+5 b d)+4 b c e^2 (13 a e+12 b d)-15 b^3 e^3+32 c^3 d^3\right )}{32 c^3}+\frac{3 e \left (b^2-4 a c\right ) \left (-4 c e (a e+4 b d)+5 b^2 e^2+16 c^2 d^2\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right )}{64 c^{7/2}}+\frac{1}{2} (d+e x)^3 \sqrt{a+b x+c x^2}+\frac{(d+e x)^2 \sqrt{a+b x+c x^2} (2 c d-b e)}{4 c} \]
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Rubi [A] time = 0.328949, antiderivative size = 245, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 28, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.143, Rules used = {832, 779, 621, 206} \[ \frac{\sqrt{a+b x+c x^2} \left (2 c e x \left (-4 c e (3 a e+2 b d)+5 b^2 e^2+8 c^2 d^2\right )-8 c^2 d e (16 a e+5 b d)+4 b c e^2 (13 a e+12 b d)-15 b^3 e^3+32 c^3 d^3\right )}{32 c^3}+\frac{3 e \left (b^2-4 a c\right ) \left (-4 c e (a e+4 b d)+5 b^2 e^2+16 c^2 d^2\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right )}{64 c^{7/2}}+\frac{1}{2} (d+e x)^3 \sqrt{a+b x+c x^2}+\frac{(d+e x)^2 \sqrt{a+b x+c x^2} (2 c d-b e)}{4 c} \]
Antiderivative was successfully verified.
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Rule 832
Rule 779
Rule 621
Rule 206
Rubi steps
\begin{align*} \int \frac{(b+2 c x) (d+e x)^3}{\sqrt{a+b x+c x^2}} \, dx &=\frac{1}{2} (d+e x)^3 \sqrt{a+b x+c x^2}+\frac{\int \frac{(d+e x)^2 (3 c (b d-2 a e)+3 c (2 c d-b e) x)}{\sqrt{a+b x+c x^2}} \, dx}{4 c}\\ &=\frac{(2 c d-b e) (d+e x)^2 \sqrt{a+b x+c x^2}}{4 c}+\frac{1}{2} (d+e x)^3 \sqrt{a+b x+c x^2}+\frac{\int \frac{(d+e x) \left (\frac{3}{2} c \left (b^2 d e-20 a c d e+4 b \left (c d^2+a e^2\right )\right )+\frac{3}{2} c \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) x\right )}{\sqrt{a+b x+c x^2}} \, dx}{12 c^2}\\ &=\frac{(2 c d-b e) (d+e x)^2 \sqrt{a+b x+c x^2}}{4 c}+\frac{1}{2} (d+e x)^3 \sqrt{a+b x+c x^2}+\frac{\left (32 c^3 d^3-15 b^3 e^3+4 b c e^2 (12 b d+13 a e)-8 c^2 d e (5 b d+16 a e)+2 c e \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) x\right ) \sqrt{a+b x+c x^2}}{32 c^3}+\frac{\left (3 \left (b^2-4 a c\right ) e \left (16 c^2 d^2+5 b^2 e^2-4 c e (4 b d+a e)\right )\right ) \int \frac{1}{\sqrt{a+b x+c x^2}} \, dx}{64 c^3}\\ &=\frac{(2 c d-b e) (d+e x)^2 \sqrt{a+b x+c x^2}}{4 c}+\frac{1}{2} (d+e x)^3 \sqrt{a+b x+c x^2}+\frac{\left (32 c^3 d^3-15 b^3 e^3+4 b c e^2 (12 b d+13 a e)-8 c^2 d e (5 b d+16 a e)+2 c e \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) x\right ) \sqrt{a+b x+c x^2}}{32 c^3}+\frac{\left (3 \left (b^2-4 a c\right ) e \left (16 c^2 d^2+5 b^2 e^2-4 c e (4 b d+a e)\right )\right ) \operatorname{Subst}\left (\int \frac{1}{4 c-x^2} \, dx,x,\frac{b+2 c x}{\sqrt{a+b x+c x^2}}\right )}{32 c^3}\\ &=\frac{(2 c d-b e) (d+e x)^2 \sqrt{a+b x+c x^2}}{4 c}+\frac{1}{2} (d+e x)^3 \sqrt{a+b x+c x^2}+\frac{\left (32 c^3 d^3-15 b^3 e^3+4 b c e^2 (12 b d+13 a e)-8 c^2 d e (5 b d+16 a e)+2 c e \left (8 c^2 d^2+5 b^2 e^2-4 c e (2 b d+3 a e)\right ) x\right ) \sqrt{a+b x+c x^2}}{32 c^3}+\frac{3 \left (b^2-4 a c\right ) e \left (16 c^2 d^2+5 b^2 e^2-4 c e (4 b d+a e)\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+b x+c x^2}}\right )}{64 c^{7/2}}\\ \end{align*}
Mathematica [A] time = 0.426949, size = 302, normalized size = 1.23 \[ \frac{-4 a^2 c e^2 (-13 b e+32 c d+6 c e x)+a \left (2 b^2 c e^2 (24 d+31 e x)-15 b^3 e^3+4 b c^2 e \left (-12 d^2-40 d e x+5 e^2 x^2\right )+8 c^3 \left (12 d^2 e x+8 d^3-8 d e^2 x^2-e^3 x^3\right )\right )+x (b+c x) \left (2 b^2 c e^2 (24 d+5 e x)-15 b^3 e^3-8 b c^2 e \left (6 d^2+4 d e x+e^2 x^2\right )+16 c^3 \left (6 d^2 e x+4 d^3+4 d e^2 x^2+e^3 x^3\right )\right )}{32 c^3 \sqrt{a+x (b+c x)}}+\frac{3 e \left (b^2-4 a c\right ) \left (-4 c e (a e+4 b d)+5 b^2 e^2+16 c^2 d^2\right ) \tanh ^{-1}\left (\frac{b+2 c x}{2 \sqrt{c} \sqrt{a+x (b+c x)}}\right )}{64 c^{7/2}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.014, size = 539, normalized size = 2.2 \begin{align*} 2\,\sqrt{c{x}^{2}+bx+a}{d}^{3}+3\,{\frac{abd{e}^{2}}{{c}^{3/2}}\ln \left ({\frac{b/2+cx}{\sqrt{c}}}+\sqrt{c{x}^{2}+bx+a} \right ) }-3\,{\frac{a{d}^{2}e}{\sqrt{c}}\ln \left ({\frac{b/2+cx}{\sqrt{c}}}+\sqrt{c{x}^{2}+bx+a} \right ) }+2\,{x}^{2}\sqrt{c{x}^{2}+bx+a}d{e}^{2}+3\,x\sqrt{c{x}^{2}+bx+a}{d}^{2}e+{\frac{3\,{b}^{2}{d}^{2}e}{4}\ln \left ({ \left ({\frac{b}{2}}+cx \right ){\frac{1}{\sqrt{c}}}}+\sqrt{c{x}^{2}+bx+a} \right ){c}^{-{\frac{3}{2}}}}-{\frac{bxd{e}^{2}}{c}\sqrt{c{x}^{2}+bx+a}}-{\frac{3\,{b}^{3}d{e}^{2}}{4}\ln \left ({ \left ({\frac{b}{2}}+cx \right ){\frac{1}{\sqrt{c}}}}+\sqrt{c{x}^{2}+bx+a} \right ){c}^{-{\frac{5}{2}}}}-{\frac{15\,{b}^{3}{e}^{3}}{32\,{c}^{3}}\sqrt{c{x}^{2}+bx+a}}-{\frac{9\,a{b}^{2}{e}^{3}}{8}\ln \left ({ \left ({\frac{b}{2}}+cx \right ){\frac{1}{\sqrt{c}}}}+\sqrt{c{x}^{2}+bx+a} \right ){c}^{-{\frac{5}{2}}}}+{\frac{{e}^{3}{x}^{3}}{2}\sqrt{c{x}^{2}+bx+a}}-4\,{\frac{a\sqrt{c{x}^{2}+bx+a}d{e}^{2}}{c}}-{\frac{3\,b{d}^{2}e}{2\,c}\sqrt{c{x}^{2}+bx+a}}+{\frac{3\,{b}^{2}d{e}^{2}}{2\,{c}^{2}}\sqrt{c{x}^{2}+bx+a}}+{\frac{3\,{e}^{3}{a}^{2}}{4}\ln \left ({ \left ({\frac{b}{2}}+cx \right ){\frac{1}{\sqrt{c}}}}+\sqrt{c{x}^{2}+bx+a} \right ){c}^{-{\frac{3}{2}}}}-{\frac{b{e}^{3}{x}^{2}}{4\,c}\sqrt{c{x}^{2}+bx+a}}+{\frac{5\,{e}^{3}{b}^{2}x}{16\,{c}^{2}}\sqrt{c{x}^{2}+bx+a}}+{\frac{15\,{b}^{4}{e}^{3}}{64}\ln \left ({ \left ({\frac{b}{2}}+cx \right ){\frac{1}{\sqrt{c}}}}+\sqrt{c{x}^{2}+bx+a} \right ){c}^{-{\frac{7}{2}}}}+{\frac{13\,ab{e}^{3}}{8\,{c}^{2}}\sqrt{c{x}^{2}+bx+a}}-{\frac{3\,a{e}^{3}x}{4\,c}\sqrt{c{x}^{2}+bx+a}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 2.44127, size = 1207, normalized size = 4.93 \begin{align*} \left [\frac{3 \,{\left (16 \,{\left (b^{2} c^{2} - 4 \, a c^{3}\right )} d^{2} e - 16 \,{\left (b^{3} c - 4 \, a b c^{2}\right )} d e^{2} +{\left (5 \, b^{4} - 24 \, a b^{2} c + 16 \, a^{2} c^{2}\right )} e^{3}\right )} \sqrt{c} \log \left (-8 \, c^{2} x^{2} - 8 \, b c x - b^{2} - 4 \, \sqrt{c x^{2} + b x + a}{\left (2 \, c x + b\right )} \sqrt{c} - 4 \, a c\right ) + 4 \,{\left (16 \, c^{4} e^{3} x^{3} + 64 \, c^{4} d^{3} - 48 \, b c^{3} d^{2} e + 16 \,{\left (3 \, b^{2} c^{2} - 8 \, a c^{3}\right )} d e^{2} -{\left (15 \, b^{3} c - 52 \, a b c^{2}\right )} e^{3} + 8 \,{\left (8 \, c^{4} d e^{2} - b c^{3} e^{3}\right )} x^{2} + 2 \,{\left (48 \, c^{4} d^{2} e - 16 \, b c^{3} d e^{2} +{\left (5 \, b^{2} c^{2} - 12 \, a c^{3}\right )} e^{3}\right )} x\right )} \sqrt{c x^{2} + b x + a}}{128 \, c^{4}}, -\frac{3 \,{\left (16 \,{\left (b^{2} c^{2} - 4 \, a c^{3}\right )} d^{2} e - 16 \,{\left (b^{3} c - 4 \, a b c^{2}\right )} d e^{2} +{\left (5 \, b^{4} - 24 \, a b^{2} c + 16 \, a^{2} c^{2}\right )} e^{3}\right )} \sqrt{-c} \arctan \left (\frac{\sqrt{c x^{2} + b x + a}{\left (2 \, c x + b\right )} \sqrt{-c}}{2 \,{\left (c^{2} x^{2} + b c x + a c\right )}}\right ) - 2 \,{\left (16 \, c^{4} e^{3} x^{3} + 64 \, c^{4} d^{3} - 48 \, b c^{3} d^{2} e + 16 \,{\left (3 \, b^{2} c^{2} - 8 \, a c^{3}\right )} d e^{2} -{\left (15 \, b^{3} c - 52 \, a b c^{2}\right )} e^{3} + 8 \,{\left (8 \, c^{4} d e^{2} - b c^{3} e^{3}\right )} x^{2} + 2 \,{\left (48 \, c^{4} d^{2} e - 16 \, b c^{3} d e^{2} +{\left (5 \, b^{2} c^{2} - 12 \, a c^{3}\right )} e^{3}\right )} x\right )} \sqrt{c x^{2} + b x + a}}{64 \, c^{4}}\right ] \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\left (b + 2 c x\right ) \left (d + e x\right )^{3}}{\sqrt{a + b x + c x^{2}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 2.02327, size = 340, normalized size = 1.39 \begin{align*} \frac{1}{32} \, \sqrt{c x^{2} + b x + a}{\left (2 \,{\left (4 \,{\left (2 \, x e^{3} + \frac{8 \, c^{3} d e^{2} - b c^{2} e^{3}}{c^{3}}\right )} x + \frac{48 \, c^{3} d^{2} e - 16 \, b c^{2} d e^{2} + 5 \, b^{2} c e^{3} - 12 \, a c^{2} e^{3}}{c^{3}}\right )} x + \frac{64 \, c^{3} d^{3} - 48 \, b c^{2} d^{2} e + 48 \, b^{2} c d e^{2} - 128 \, a c^{2} d e^{2} - 15 \, b^{3} e^{3} + 52 \, a b c e^{3}}{c^{3}}\right )} - \frac{3 \,{\left (16 \, b^{2} c^{2} d^{2} e - 64 \, a c^{3} d^{2} e - 16 \, b^{3} c d e^{2} + 64 \, a b c^{2} d e^{2} + 5 \, b^{4} e^{3} - 24 \, a b^{2} c e^{3} + 16 \, a^{2} c^{2} e^{3}\right )} \log \left ({\left | -2 \,{\left (\sqrt{c} x - \sqrt{c x^{2} + b x + a}\right )} \sqrt{c} - b \right |}\right )}{64 \, c^{\frac{7}{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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